Optimal. Leaf size=337 \[ \frac {2 \sqrt {2 \pi } b^{3/2} f^2 (d e-c f) S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {b^2 f^3 \text {Si}\left (\frac {b}{(c+d x)^2}\right )}{4 d^4}-\frac {3 b f (d e-c f)^2 \text {Ci}\left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {f^2 (c+d x)^3 (d e-c f) \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {2 b f^2 (c+d x) (d e-c f) \cos \left (\frac {b}{(c+d x)^2}\right )}{d^4}-\frac {\sqrt {2 \pi } \sqrt {b} (d e-c f)^3 C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {3 f (c+d x)^2 (d e-c f)^2 \sin \left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {(c+d x) (d e-c f)^3 \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {f^3 (c+d x)^4 \sin \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}+\frac {b f^3 (c+d x)^2 \cos \left (\frac {b}{(c+d x)^2}\right )}{4 d^4} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.42, antiderivative size = 337, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 11, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.611, Rules used = {3433, 3359, 3387, 3352, 3379, 3297, 3302, 3409, 3388, 3351, 3299} \[ \frac {2 \sqrt {2 \pi } b^{3/2} f^2 (d e-c f) S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {b^2 f^3 \text {Si}\left (\frac {b}{(c+d x)^2}\right )}{4 d^4}-\frac {3 b f (d e-c f)^2 \text {CosIntegral}\left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {f^2 (c+d x)^3 (d e-c f) \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {2 b f^2 (c+d x) (d e-c f) \cos \left (\frac {b}{(c+d x)^2}\right )}{d^4}-\frac {\sqrt {2 \pi } \sqrt {b} (d e-c f)^3 \text {FresnelC}\left (\frac {\sqrt {\frac {2}{\pi }} \sqrt {b}}{c+d x}\right )}{d^4}+\frac {3 f (c+d x)^2 (d e-c f)^2 \sin \left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {(c+d x) (d e-c f)^3 \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {f^3 (c+d x)^4 \sin \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}+\frac {b f^3 (c+d x)^2 \cos \left (\frac {b}{(c+d x)^2}\right )}{4 d^4} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 3297
Rule 3299
Rule 3302
Rule 3351
Rule 3352
Rule 3359
Rule 3379
Rule 3387
Rule 3388
Rule 3409
Rule 3433
Rubi steps
\begin {align*} \int (e+f x)^3 \sin \left (\frac {b}{(c+d x)^2}\right ) \, dx &=\frac {\operatorname {Subst}\left (\int \left (d^3 e^3 \left (1-\frac {c f \left (3 d^2 e^2-3 c d e f+c^2 f^2\right )}{d^3 e^3}\right ) \sin \left (\frac {b}{x^2}\right )+3 d^2 e^2 f \left (1+\frac {c f (-2 d e+c f)}{d^2 e^2}\right ) x \sin \left (\frac {b}{x^2}\right )+3 d e f^2 \left (1-\frac {c f}{d e}\right ) x^2 \sin \left (\frac {b}{x^2}\right )+f^3 x^3 \sin \left (\frac {b}{x^2}\right )\right ) \, dx,x,c+d x\right )}{d^4}\\ &=\frac {f^3 \operatorname {Subst}\left (\int x^3 \sin \left (\frac {b}{x^2}\right ) \, dx,x,c+d x\right )}{d^4}+\frac {\left (3 f^2 (d e-c f)\right ) \operatorname {Subst}\left (\int x^2 \sin \left (\frac {b}{x^2}\right ) \, dx,x,c+d x\right )}{d^4}+\frac {\left (3 f (d e-c f)^2\right ) \operatorname {Subst}\left (\int x \sin \left (\frac {b}{x^2}\right ) \, dx,x,c+d x\right )}{d^4}+\frac {(d e-c f)^3 \operatorname {Subst}\left (\int \sin \left (\frac {b}{x^2}\right ) \, dx,x,c+d x\right )}{d^4}\\ &=-\frac {f^3 \operatorname {Subst}\left (\int \frac {\sin (b x)}{x^3} \, dx,x,\frac {1}{(c+d x)^2}\right )}{2 d^4}-\frac {\left (3 f^2 (d e-c f)\right ) \operatorname {Subst}\left (\int \frac {\sin \left (b x^2\right )}{x^4} \, dx,x,\frac {1}{c+d x}\right )}{d^4}-\frac {\left (3 f (d e-c f)^2\right ) \operatorname {Subst}\left (\int \frac {\sin (b x)}{x^2} \, dx,x,\frac {1}{(c+d x)^2}\right )}{2 d^4}-\frac {(d e-c f)^3 \operatorname {Subst}\left (\int \frac {\sin \left (b x^2\right )}{x^2} \, dx,x,\frac {1}{c+d x}\right )}{d^4}\\ &=\frac {(d e-c f)^3 (c+d x) \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {3 f (d e-c f)^2 (c+d x)^2 \sin \left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {f^2 (d e-c f) (c+d x)^3 \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {f^3 (c+d x)^4 \sin \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}-\frac {\left (b f^3\right ) \operatorname {Subst}\left (\int \frac {\cos (b x)}{x^2} \, dx,x,\frac {1}{(c+d x)^2}\right )}{4 d^4}-\frac {\left (2 b f^2 (d e-c f)\right ) \operatorname {Subst}\left (\int \frac {\cos \left (b x^2\right )}{x^2} \, dx,x,\frac {1}{c+d x}\right )}{d^4}-\frac {\left (3 b f (d e-c f)^2\right ) \operatorname {Subst}\left (\int \frac {\cos (b x)}{x} \, dx,x,\frac {1}{(c+d x)^2}\right )}{2 d^4}-\frac {\left (2 b (d e-c f)^3\right ) \operatorname {Subst}\left (\int \cos \left (b x^2\right ) \, dx,x,\frac {1}{c+d x}\right )}{d^4}\\ &=\frac {2 b f^2 (d e-c f) (c+d x) \cos \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {b f^3 (c+d x)^2 \cos \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}-\frac {3 b f (d e-c f)^2 \text {Ci}\left (\frac {b}{(c+d x)^2}\right )}{2 d^4}-\frac {\sqrt {b} (d e-c f)^3 \sqrt {2 \pi } C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {(d e-c f)^3 (c+d x) \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {3 f (d e-c f)^2 (c+d x)^2 \sin \left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {f^2 (d e-c f) (c+d x)^3 \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {f^3 (c+d x)^4 \sin \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}+\frac {\left (b^2 f^3\right ) \operatorname {Subst}\left (\int \frac {\sin (b x)}{x} \, dx,x,\frac {1}{(c+d x)^2}\right )}{4 d^4}+\frac {\left (4 b^2 f^2 (d e-c f)\right ) \operatorname {Subst}\left (\int \sin \left (b x^2\right ) \, dx,x,\frac {1}{c+d x}\right )}{d^4}\\ &=\frac {2 b f^2 (d e-c f) (c+d x) \cos \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {b f^3 (c+d x)^2 \cos \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}-\frac {3 b f (d e-c f)^2 \text {Ci}\left (\frac {b}{(c+d x)^2}\right )}{2 d^4}-\frac {\sqrt {b} (d e-c f)^3 \sqrt {2 \pi } C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {2 b^{3/2} f^2 (d e-c f) \sqrt {2 \pi } S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )}{d^4}+\frac {(d e-c f)^3 (c+d x) \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {3 f (d e-c f)^2 (c+d x)^2 \sin \left (\frac {b}{(c+d x)^2}\right )}{2 d^4}+\frac {f^2 (d e-c f) (c+d x)^3 \sin \left (\frac {b}{(c+d x)^2}\right )}{d^4}+\frac {f^3 (c+d x)^4 \sin \left (\frac {b}{(c+d x)^2}\right )}{4 d^4}+\frac {b^2 f^3 \text {Si}\left (\frac {b}{(c+d x)^2}\right )}{4 d^4}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.93, size = 440, normalized size = 1.31 \[ \frac {8 \sqrt {2 \pi } b^{3/2} d e f^2 S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )-8 \sqrt {2 \pi } b^{3/2} c f^3 S\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )+b^2 f^3 \text {Si}\left (\frac {b}{(c+d x)^2}\right )+c^4 \left (-f^3\right ) \sin \left (\frac {b}{(c+d x)^2}\right )+4 c^3 d e f^2 \sin \left (\frac {b}{(c+d x)^2}\right )-6 c^2 d^2 e^2 f \sin \left (\frac {b}{(c+d x)^2}\right )-7 b c^2 f^3 \cos \left (\frac {b}{(c+d x)^2}\right )-6 b f (d e-c f)^2 \text {Ci}\left (\frac {b}{(c+d x)^2}\right )+4 d^4 e^3 x \sin \left (\frac {b}{(c+d x)^2}\right )+6 d^4 e^2 f x^2 \sin \left (\frac {b}{(c+d x)^2}\right )+4 d^4 e f^2 x^3 \sin \left (\frac {b}{(c+d x)^2}\right )+d^4 f^3 x^4 \sin \left (\frac {b}{(c+d x)^2}\right )+4 c d^3 e^3 \sin \left (\frac {b}{(c+d x)^2}\right )+8 b d^2 e f^2 x \cos \left (\frac {b}{(c+d x)^2}\right )+b d^2 f^3 x^2 \cos \left (\frac {b}{(c+d x)^2}\right )+8 b c d e f^2 \cos \left (\frac {b}{(c+d x)^2}\right )-4 \sqrt {2 \pi } \sqrt {b} (d e-c f)^3 C\left (\frac {\sqrt {b} \sqrt {\frac {2}{\pi }}}{c+d x}\right )-6 b c d f^3 x \cos \left (\frac {b}{(c+d x)^2}\right )}{4 d^4} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.75, size = 449, normalized size = 1.33 \[ \frac {b^{2} f^{3} \operatorname {Si}\left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - 4 \, \sqrt {2} \pi {\left (d^{4} e^{3} - 3 \, c d^{3} e^{2} f + 3 \, c^{2} d^{2} e f^{2} - c^{3} d f^{3}\right )} \sqrt {\frac {b}{\pi d^{2}}} \operatorname {C}\left (\frac {\sqrt {2} d \sqrt {\frac {b}{\pi d^{2}}}}{d x + c}\right ) + 8 \, \sqrt {2} \pi {\left (b d^{2} e f^{2} - b c d f^{3}\right )} \sqrt {\frac {b}{\pi d^{2}}} \operatorname {S}\left (\frac {\sqrt {2} d \sqrt {\frac {b}{\pi d^{2}}}}{d x + c}\right ) + {\left (b d^{2} f^{3} x^{2} + 8 \, b c d e f^{2} - 7 \, b c^{2} f^{3} + 2 \, {\left (4 \, b d^{2} e f^{2} - 3 \, b c d f^{3}\right )} x\right )} \cos \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - 3 \, {\left (b d^{2} e^{2} f - 2 \, b c d e f^{2} + b c^{2} f^{3}\right )} \operatorname {Ci}\left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - 3 \, {\left (b d^{2} e^{2} f - 2 \, b c d e f^{2} + b c^{2} f^{3}\right )} \operatorname {Ci}\left (-\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) + {\left (d^{4} f^{3} x^{4} + 4 \, d^{4} e f^{2} x^{3} + 6 \, d^{4} e^{2} f x^{2} + 4 \, d^{4} e^{3} x + 4 \, c d^{3} e^{3} - 6 \, c^{2} d^{2} e^{2} f + 4 \, c^{3} d e f^{2} - c^{4} f^{3}\right )} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{4 \, d^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (f x + e\right )}^{3} \sin \left (\frac {b}{{\left (d x + c\right )}^{2}}\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [A] time = 0.03, size = 365, normalized size = 1.08 \[ \frac {-\left (c^{3} f^{3}-3 c^{2} d e \,f^{2}+3 c \,d^{2} e^{2} f -d^{3} e^{3}\right ) \left (d x +c \right ) \sin \left (\frac {b}{\left (d x +c \right )^{2}}\right )+\left (c^{3} f^{3}-3 c^{2} d e \,f^{2}+3 c \,d^{2} e^{2} f -d^{3} e^{3}\right ) \sqrt {b}\, \sqrt {2}\, \sqrt {\pi }\, \FresnelC \left (\frac {\sqrt {b}\, \sqrt {2}}{\sqrt {\pi }\, \left (d x +c \right )}\right )-\frac {\left (-3 c^{2} f^{3}+6 c d e \,f^{2}-3 d^{2} e^{2} f \right ) \left (d x +c \right )^{2} \sin \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{2}+\frac {\left (-3 c^{2} f^{3}+6 c d e \,f^{2}-3 d^{2} e^{2} f \right ) b \Ci \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{2}-\frac {\left (3 c \,f^{3}-3 f^{2} e d \right ) \left (d x +c \right )^{3} \sin \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{3}+\frac {2 \left (3 c \,f^{3}-3 f^{2} e d \right ) b \left (-\left (d x +c \right ) \cos \left (\frac {b}{\left (d x +c \right )^{2}}\right )-\sqrt {b}\, \sqrt {2}\, \sqrt {\pi }\, \mathrm {S}\left (\frac {\sqrt {b}\, \sqrt {2}}{\sqrt {\pi }\, \left (d x +c \right )}\right )\right )}{3}+\frac {f^{3} \left (d x +c \right )^{4} \sin \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{4}-\frac {f^{3} b \left (-\frac {\left (d x +c \right )^{2} \cos \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{2}-\frac {b \Si \left (\frac {b}{\left (d x +c \right )^{2}}\right )}{2}\right )}{2}}{d^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {-{\left (\frac {4 \, c^{3} e f^{2} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{d^{3}} - \frac {3 \, c^{4} f^{3} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{d^{4}} - 2 \, \int -\frac {2 \, {\left (3 \, {\left (b d^{3} e^{2} f - 2 \, b c d^{2} e f^{2} + b c^{2} d f^{3}\right )} x^{2} + 2 \, {\left (b d^{3} e^{3} - 3 \, b c^{2} d e f^{2} + 2 \, b c^{3} f^{3}\right )} x\right )} \cos \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - {\left (b^{2} d f^{3} x^{2} + 2 \, {\left (4 \, b^{2} d e f^{2} - 3 \, b^{2} c f^{3}\right )} x\right )} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{2 \, {\left (d^{5} x^{3} + 3 \, c d^{4} x^{2} + 3 \, c^{2} d^{3} x + c^{3} d^{2}\right )}}\,{d x} - 2 \, \int -\frac {2 \, {\left (3 \, {\left (b d^{3} e^{2} f - 2 \, b c d^{2} e f^{2} + b c^{2} d f^{3}\right )} x^{2} + 2 \, {\left (b d^{3} e^{3} - 3 \, b c^{2} d e f^{2} + 2 \, b c^{3} f^{3}\right )} x\right )} \cos \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - {\left (b^{2} d f^{3} x^{2} + 2 \, {\left (4 \, b^{2} d e f^{2} - 3 \, b^{2} c f^{3}\right )} x\right )} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{2 \, {\left ({\left (d^{5} x^{3} + 3 \, c d^{4} x^{2} + 3 \, c^{2} d^{3} x + c^{3} d^{2}\right )} \cos \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )^{2} + {\left (d^{5} x^{3} + 3 \, c d^{4} x^{2} + 3 \, c^{2} d^{3} x + c^{3} d^{2}\right )} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )^{2}\right )}}\,{d x}\right )} d^{3} - {\left (b d f^{3} x^{2} + 2 \, {\left (4 \, b d e f^{2} - 3 \, b c f^{3}\right )} x\right )} \cos \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right ) - {\left (d^{3} f^{3} x^{4} + 4 \, d^{3} e f^{2} x^{3} + 6 \, d^{3} e^{2} f x^{2} + 4 \, d^{3} e^{3} x\right )} \sin \left (\frac {b}{d^{2} x^{2} + 2 \, c d x + c^{2}}\right )}{4 \, d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \sin \left (\frac {b}{{\left (c+d\,x\right )}^2}\right )\,{\left (e+f\,x\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________